0=-16t^2+11t+85

Solution for 0=-16t^2+11t+85 equation:

0=-16t^2+11t+85

We move all terms to the left:

0-(-16t^2+11t+85)=0

We add all the numbers together, and all the variables

-(-16t^2+11t+85)=0

We get rid of parentheses

16t^2-11t-85=0

a = 16; b = -11; c = -85;
Δ = b2-4ac
Δ = -112-4·16·(-85)
Δ = 5561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{5561}}{2*16}=\frac{11-\sqrt{5561}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{5561}}{2*16}=\frac{11+\sqrt{5561}}{32}
$